2+2sinx=4cos^2x

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Solution for 2+2sinx=4cos^2x equation: 


Simplifying
2 + 2sinx = 4cos2x

Solving
2 + 2insx = 4cos2x

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2insx = -2 + 4cos2x

Combine like terms: 2 + -2 = 0
0 + 2insx = -2 + 4cos2x
2insx = -2 + 4cos2x

Divide each side by '2nsx'.
i = -1n-1s-1x-1 + 2cn-1os

Simplifying
i = -1n-1s-1x-1 + 2cn-1os

Reorder the terms:
i = 2cn-1os + -1n-1s-1x-1

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